Odpowiedź:
162, a², a³, 6
[tex]an = {a}^{1} \times {q}^{n - 1} [/tex]
a⁴ = a¹ × q³
6 = 162 × q³
q³ = 6/162
q³ = 1/27
q = 1/3
a² = 162 × (1/3)¹
a² = 54
a³ = 162 × (1/3)²
a³ = 18
