No raczej, że się da :D
[tex]c^2=3^2+(2\sqrt{10})^2\\\\c^2=9+2^2\cdot(\sqrt{10})^2\\\\c^2=9+4\cdot10\\\\c^2=9+40\\\\c^2=49\\\\c=\sqrt{49}\\\\\huge\boxed{c=7}[/tex]
