Odpowiedź :
[tex]dane:\\S_1 = 10 \ cm^{2}\\F_1 = 10 \ N\\S_2 = 150 \ cm^{2}\\szukane:\\F_2 = ?\\\\Z \ prawa \ Pascala\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2}\\\\F_2\cdot S_1 = F_1\cdot S_2 \ \ /:S_1\\\\F_2 = F_1\cdot\frac{S_2}{S_1}\\\\F_2 = 10 \ N\cdot\frac{150 \ cm^{2}}{10 \ cm^{2}}\\\\F_2 = 10 \ N \cdot15\\\\F_2 = 150 \ N[/tex]