Odpowiedź :
[tex]d = 10 \ cm \ \ \rightarrow \ \ r = \frac{d}{2} =5 \ cm\\H = 11 \ cm\\\\P_{p} = \pi r^{2} = \pi \cdot5^{2} = 25 \pi \ cm^{2}\\\\V = P_{p}\cdot H = 25\pi\cdot11 = 275\pi \ cm^{3}\\\\Odp. \ A.[/tex]
[tex]d = 10 \ cm \ \ \rightarrow \ \ r = \frac{d}{2} =5 \ cm\\H = 11 \ cm\\\\P_{p} = \pi r^{2} = \pi \cdot5^{2} = 25 \pi \ cm^{2}\\\\V = P_{p}\cdot H = 25\pi\cdot11 = 275\pi \ cm^{3}\\\\Odp. \ A.[/tex]