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(7-2)^2-3^2=
9-4^2:2^3=
5+3*2^2=
proszę o pomoc


Odpowiedź :

a)

[tex] {(7 - 2)}^{2} - {3}^{2} = {5}^{2} - {3}^{2} = 25 - 9 = 16[/tex]

b)

[tex]9 - {4}^{2} \div {2}^{3} = 9 - 16 \div 8 = 9 - 2 = 7[/tex]

c)

[tex]5 + 3 \times {2}^{2} = 5 + 3 \times 4 = 5 + 12 = 17[/tex]

[tex]1] \ (7-2)^2-3^2=5^2-3^2=25-9=16\\\\2] \ 9-4^2:2^3=9-16:8=9-2=7\\\\3] \ 5+3\cdot2^2=5+3\cdot4=5+12=17[/tex]