Chemia! klasa 8, zadanie 29 strina 119 ćwiczenia

wzór sum: C12H22O11
mcz=(12*12+1*22+16*11)u=342 u
mC:mH:mO=12*12:22:16*11=144:22:176=72:11:88
%C=(12*12u÷342u)*100%=42,1%
%H=(22u÷342u)*100%=6,4%
%O=(11*16u÷342u)*100%=51,5%