Odpowiedź :
[tex]dane:\\S_1= 0,025 \ m^{2}}\\S = 2S_1 = 2\cdot0,025 \ m^{2} = 0,05 \ m^{2}\\F = 600 \ N\\szukane:\\p = ?\\\\p = \frac{F}{S}\\\\p = \frac{600 \ N}{0,05 \ m^{2}}\\\\p = 12 \ 000 \ Pa = 120 \ hPa\\\\(1 \ hPa = 100 \ Pa)[/tex]
[tex]dane:\\S_1= 0,025 \ m^{2}}\\S = 2S_1 = 2\cdot0,025 \ m^{2} = 0,05 \ m^{2}\\F = 600 \ N\\szukane:\\p = ?\\\\p = \frac{F}{S}\\\\p = \frac{600 \ N}{0,05 \ m^{2}}\\\\p = 12 \ 000 \ Pa = 120 \ hPa\\\\(1 \ hPa = 100 \ Pa)[/tex]