[tex]dane:\\p_{h} = 0,5 \ MPa = 0,5\cdot 1 \ 000 \ 000 \ Pa = 500 \ 000 \ Pa=500 \ 000 \ \frac{N}{m^{2}}\\d = 1000\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\szukane:\\h = ?\\\\Rozwiazanie\\\\p_{h} = d\cdot g\cdot h \ \ /:(d\cdot g)\\\\h = \frac{p_{h}}{d\cdot g}\\\\h = \frac{500000 \ Pa}{1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}}=\frac{500000 \ \frac{N}{m^{2}}}{10000\frac{N}{m^{3}}}=50 \ m[/tex]
Odp. Szukana głębokość h = 50 m.
