Odpowiedź :
[tex]P_{rombu} =\frac{1}{2} *d_{1} *d_{2}[/tex]
[tex]d_{1} ,d_{2} -[/tex] przekątne rombu
[tex]P=10cm^{2} \\d_{1} =10cm[/tex]
[tex]10cm^{2} =\frac{1}{2} *10cm *d_{2}[/tex]
[tex]d_{2} =2cm[/tex]
[tex]P_{rombu} =\frac{1}{2} *d_{1} *d_{2}[/tex]
[tex]d_{1} ,d_{2} -[/tex] przekątne rombu
[tex]P=10cm^{2} \\d_{1} =10cm[/tex]
[tex]10cm^{2} =\frac{1}{2} *10cm *d_{2}[/tex]
[tex]d_{2} =2cm[/tex]