g)
[tex]\frac{(2x+1)(x+3)}{x(4x^2-1)}=0\\\\x(4x^2-1)\neq0\\\\x(2x+1)(2x-1)\neq0\\\\x\neq0, \ x\neq-\frac{1}{2}, \ x\neq=\frac{1}{2}\\\\(2x+1)(x+3)=0\\\\2x+1=0 \ \vee \ x+3=0\\\\x=-\frac{1}{2}\notin\mathbb{D} \ \vee \ \boxed{x=-3}\in\mathbb{D}[/tex]
Odp. x = -3
h)
[tex]\frac{x^3+2x^2+x}{(x+1)(x+2)}=0\\\\(x+1)(x+2)\neq0\\\\x\neq-1, \ x\neq-2\\\\x^3+2x^2+x=0\\\\x(x^2+2x+1)=0\\\\x=0 \ \vee \ x^2+2x+1=0\\\\x=0 \ \vee \ (x+1)^2=0\\\\\boxed{x=0}\in\mathbb{D} \ \vee \ x=-1\notin\mathbb{D}[/tex]
Odp. x = 0
i)
[tex]\frac{x^3-9x}{x^2-6x+9}=0\\\\x^2-6x+9\neq0\\\\(x-3)^2\neq0\\\\x\neq3\\\\x^3-9x=0\\\\x(x^2-9)=0\\\\x(x+3)(x-3)=0\\\\\boxed{x=0}\in\mathbb{D} \ \vee \ \boxed{x=-3}\in\mathbb{D} \ \vee \ x=3\notin\mathbb{D}[/tex]
Odp. x = 0 lub x = -3.
