[tex]dane:\\F = 1 \ N\\a = 3\frac{m}{s^{2}}\\szukane:\\m = ?\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ \rightarrow \ \ m = \frac{F}{a}\\\\m = \frac{1 \ N}{3\frac{m}{s^{2}}} = \frac{1 \ kg\cdot\frac{m}{s^{2}}}{3\frac{m}{s^{2}}} =\frac{1}{3} \ kg \approx0,333 \ kg[/tex]
