Odpowiedź :
a) 2Li+2H2O--->2LiOH+H2
b) BaO+H2O--->Ba(OH)2
c) CrCl3+3KOH--->Cr(OH)3↓+3KCl
d) SnBr2+2NaOH--->Sn(OH)2↓+2NaBr
e) Bi2(SO4)3+6LiOH--->2Bi(OH)3↓+3Li2SO4
a) 2Li+2H2O--->2LiOH+H2
b) BaO+H2O--->Ba(OH)2
c) CrCl3+3KOH--->Cr(OH)3↓+3KCl
d) SnBr2+2NaOH--->Sn(OH)2↓+2NaBr
e) Bi2(SO4)3+6LiOH--->2Bi(OH)3↓+3Li2SO4