Odpowiedź :
Wzory:
[tex]V = a \cdot b \cdot c\\Pc = 2(ab+ac+bc)[/tex]
Dane:
[tex]a = 4dm = 40cm\\b = 3cm\\c = 2m = 200cm[/tex]
Liczymy objętość (V):
[tex]V = a \cdot b \cdot c\\V = 40cm \cdot 3cm \cdot 200cm = \boxed{24000cm^3}[/tex]
Liczymy pole całkowite (Pc):
[tex]Pc = 2(ab+ac+bc)\\Pc = 2(40cm \cdot 3cm + 40cm \cdot 200cm + 3cm \cdot 200cm) = 2 \cdot 8720cm = \boxed{17440cm^2}[/tex]
Zadanie
a = 4 dm = 40 cm
b = 3 cm
c = 2 m = 200 cm
Pc = 2ab + 2ac + 2bc
Pc = 2 · 40 · 3 + 2 · 40 · 200 + 2 · 3 · 200 = 240 + 16000 + 1200 =
= 17440 cm² = 174,4 dm²
V = a · b · c
V = 40 · 3 · 200 = 24000 cm³ = 24 dm³