Odpowiedź :
[tex]dane:\\m = 300 \ dag = 3 \ kg\\a = 3\frac{m}{s^{2}}\\szukane:\\F = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ /\cdot m\\\\F = m\cdot a\\\\F = 3 \ kg\cdot3\frac{m}{s^{2}}\\\\F = 9 \ N[/tex]
[tex]dane:\\m = 300 \ dag = 3 \ kg\\a = 3\frac{m}{s^{2}}\\szukane:\\F = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ /\cdot m\\\\F = m\cdot a\\\\F = 3 \ kg\cdot3\frac{m}{s^{2}}\\\\F = 9 \ N[/tex]