ZADANIE 1
A=10
B=11
C=A+B=10+11
D=10*11=AB
6A-3B+A=A+B+C | -7A
-3B=-6A+B+C | -B
-4B=-6A+C | :4
-B=-1,5A+[tex]\frac{C}{4}[/tex]
B=1,5A-C:4
ZADANIE 2
[tex]\frac{2x+3y+Bz}{2}=D \\ \frac{2x+3y+Bz}{2}=110[/tex] |:2
x+1,5y+[tex]\frac{1}{2}[/tex]Bz=55 | : B
x+1,5y+[tex]\frac{1}{2}[/tex]z=55:[tex]\frac{B}{2}[/tex] | -(x+1,5y)
[tex]\frac{1}{2}[/tex]z=55:[tex]\frac{B}{2}[/tex]-x+1,5y | * 2
z=110:B-2x+3y
