Odpowiedź :
[tex]dane:\\m_{s} = 40 \ g\\m_{H_2O} = 800 \ g\\m_{r} = m_{s} + m_{H_2O} = 40 \ g + 800 \ g = 840 \ g\\szukane:\\C_{p} = ?\\\\C_{p} =\frac{m_{s}}{m_{r}}\cdot100\% \\\\C_{p} = \frac{40 \ g}{840 \ g}\cdot100\% = 4,76\%[/tex]
[tex]dane:\\m_{s} = 40 \ g\\m_{H_2O} = 800 \ g\\m_{r} = m_{s} + m_{H_2O} = 40 \ g + 800 \ g = 840 \ g\\szukane:\\C_{p} = ?\\\\C_{p} =\frac{m_{s}}{m_{r}}\cdot100\% \\\\C_{p} = \frac{40 \ g}{840 \ g}\cdot100\% = 4,76\%[/tex]