Odpowiedź:
a)
[tex]7n-(2n-8(n+5)) - (n - (3n-10))\\7n - (2n - 8n - 40) - (n -3n + 10)\\7n - (-6n-40) - (-2n +10)\\7n + 6n +40 +2n - 10 = 15n + 30[/tex]
b)
[tex](2ab+3b)(6a-1)-ab(3-a)\\12a^2b-2ab+18ab-3b-3ab+a^2b\\13a^2b+13ab-3b[/tex]
c)
[tex]\frac{3p^2-2p+24}{4} * \frac{1}{3} - p^2 + \frac{1}{6}p-4\\\frac{3p^2-2p+24}{12} - p^2 + \frac{1}{6}p-4\\\\\frac{3p^2-2p+24-12p^2+2p-48}{12}\\\frac{-9p^2-24}{12}\\\frac{3(-3p^2-9}{12} = \frac{-3p^2-8}{4} = -\frac{3p^2+8}{4}[/tex]
d)
[tex](x-3y)^3 = x^3 - 9x^2y + 27xy^2 - 27y^3[/tex]
Szczegółowe wyjaśnienie:
