Odpowiedź :
Zad 1
ms= 30 g
mr= mH2O+ms= 100 + 30 = 130 g
Cp= (ms÷mr)*100%
Cp= (30÷130)*100%= 23,08%
Zad 2
Cp= 54%
ms=54 g
mH2O=100-54=46 g
54 g sub-------46 g H2O
x g sub--------100 g H2O
x= 117,39 g sub
R sub= 117,39 g/100 g H2O
zad.3
V= 0,4 dm3= 400 cm3
d= 1,12 g/cm3
Cp=12%
mr=dr*Vr= 400 cm3*1,12 g/cm3=448 g
12%: 12 g KCl--------100 g r-ru
x g KCl-------- 448 g r-ru
x= 53,76 g KCl
Zad.4
3%: 3 g sub-------- 100 g r-ru
x g sub-------- 250 g r-ru
x= 7,5 g sub
Nowy roztwór:
mr= 250 + 50= 300 g
y g sub--------100 g r-ru
7,5 g sub-------- 300 g r-ru
y= 2,5 g sub
Cp= 2,5%