Proszę o pomoc!!!!!!!!Daje naj!

5)
[tex]d = 5 \sqrt{2} [/tex]
6)
[tex]h = \frac{6 \sqrt{3} }{2} = 3 \sqrt{3} [/tex]
[tex]p = \frac{6 {}^{2} \sqrt{3} }{4} = \frac{36 \sqrt{3} }{4} = 9 \sqrt{3} [/tex]