[tex]a)\\ \frac{2,4\cdot\frac{3}{4}}{2,4-\frac{3}{2}} = \frac{1,8}{2,4-1,5} = \frac{1,8}{0,9} = 2\\\\b)\\\sqrt{2\frac{1}{4}}\cdot4+\frac{8}{9}:(-1\frac{1}{3})^{3} = \sqrt{\frac{9}{4}}\cdot4 + \frac{8}{9}:(-\frac{4}{3})^{3} = \frac{3}{2}\cdot4+\frac{8}{9}:(-\frac{64}{27}) = 6+\frac{8}{9}\cdot(-\frac{27}{64})=\\\\=6-\frac{3}{8} = 5\frac{5}{8}[/tex]
