Odpowiedź :
Zadanie
3(x - 1) - 4(x - 3) = 2(x - 2)
3x - 3 - 4x + 12 = 2x - 4
-x + 9 = 2x - 4 l -9
-x = 2x - 13 l -2x
-3x = -13 l :(-3)
[tex]x=\frac{-13}{-3}\\\\x=4\frac{1}{3}[/tex]
Zadanie
3(x - 1) - 4(x - 3) = 2(x - 2)
3x - 3 - 4x + 12 = 2x - 4
-x + 9 = 2x - 4 l -9
-x = 2x - 13 l -2x
-3x = -13 l :(-3)
[tex]x=\frac{-13}{-3}\\\\x=4\frac{1}{3}[/tex]