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na zaraz serio
POMOCY PLS


Na Zaraz Serio POMOCY PLS class=

Odpowiedź :

1 4/3

2 1/3-2/3 = 1 2/3 -2/3= 1

2 13/8

3 5/8 - 7/8= 2 6/8 -7/8= 1 7/8

a)

[tex]2 \frac{1}{3} = 1 \frac{2}{3} \\ 2 \frac{1}{3} - \frac{2}{3} = 1 \frac{4}{3} - \frac{2}{3} = 1 \frac{2}{3} [/tex]

b)

[tex]3 \frac{5}{8} = 2 \frac{7}{8} \\ \: \: {} \: 3 \frac{5}{8} - \frac{7}{8} = 2 \frac{6

13}{8} - \frac{7}{8} = 2 \frac{6}{8} = 2 \frac{3}{4} [/tex]

:)

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