Odpowiedź :
[tex]Zadanie\\\\P(6,\sqrt{20})\\\\ Proporcjonalnosc\ prosta-wzor\\\\y=ax \\\\ \sqrt{20} =a\cdot6\ \ \mid:6\\\\\frac{2\sqrt{5} }{6}=a\\\\a=\frac{\sqrt{5} }{3}\\\\y=\frac{\sqrt{5}}{3}x[/tex]
[tex]Zadanie\\\\P(6,\sqrt{20})\\\\ Proporcjonalnosc\ prosta-wzor\\\\y=ax \\\\ \sqrt{20} =a\cdot6\ \ \mid:6\\\\\frac{2\sqrt{5} }{6}=a\\\\a=\frac{\sqrt{5} }{3}\\\\y=\frac{\sqrt{5}}{3}x[/tex]