zad3:
[tex]H=8\\x = 15\\\alpha =45\\sin45 = \frac{15}{y} \\\frac{\sqrt{2} }{2} = \frac{15}{y}\\y=\frac{30}{\sqrt{2} } \\Pp = \frac{1}{2}xy\\Pp = \frac{1}{2} * 15 * \frac{30}{\sqrt{2} } \\Pp = 15 * \frac{15}{\sqrt{2} } \\Pp = \frac{225}{\sqrt{2}}j^{2} \\V = \frac{1}{3}*Pp*H\\V = \frac{1}{3} * \frac{225}{\sqrt{2} } * 8 \\V = \frac{8*75}{\sqrt{2} } \\V = \frac{600}{\sqrt{2} } j^{3}[/tex]
zad4:
[tex]Pp = 6^{2} = 36j^{2}\\d = 6\sqrt{2} (przekatna podstawy)\\\frac{1}{2}d = 3\sqrt{2}\\(\frac{1}{2}d)^{2} + x^{2} = 10^{2} \\(3\sqrt{2})^{2} + x^{2} = 100\\9*2+x^{2} = 100\\x^{2} = 100-18\\x^{2} = 82\\x = \sqrt{82} = \sqrt{x} \\V = \frac{1}{3} * Pp * x\\V = \frac{1}{3} * 36 * \sqrt{82} \\V = 12\sqrt{82}j^{3}[/tex]
