Odpowiedź :
Odpowiedź:
x-((3/x)*(3-x))-(4/x)-3 = 0
x-3*x^-1*(3-x)-4*x^-1-3 = 0
x-3*x^-1*(3-x)-4/x-3 = 0
(-3*x^-1*x*(3-x))/x+(x^2)/x-4/x+(-3*x)/x = 0
x^2-3*x^-1*x*(3-x)-3*x-4 = 0
x^2+3*x-3*x-9-4 = 0
x^2+3*x-3*x-13 = 0
x^2-13 = 0
(x^2-13)/x = 0
(x^2-13)/x = 0 / * x
x^2-13 = 0
1*x^2 = 13 // : 1
x^2 = 13
x^2 = 13 / * 1/2
x = 13^(1/2)
x = 13^(1/2) lub x = -13*(1/2)
x = { 13^(1/2), -13^(1/2) }