Odpowiedź :
[tex]1\frac{2}{3}+y=2\frac{3}{4} \\\\ y+\frac{5}{3} = \frac{11}{4} \ \ \ \ \ /-\frac{5}{3} \\\\y = \frac{13}{12}[/tex]
[tex]1 \frac{2}{3} + y = 2 \frac{3}{4} [/tex]
1 i 2/3 odejmujemy obustronnie
[tex]y = 2 \frac{3}{4} - 1 \frac{2}{3} [/tex]
Obliczamy
[tex]y = 1 \frac{1}{12} [/tex]