Odpowiedź :
[tex]F = 1200 \ N\\a = 3\frac{m}{s^{2}} = 3\frac{N}{kg}\\m = ?\\\\Z \ II \ zasady \ dynamiki:\\\\a = \frac{F}{m} \ \ \rightarrow \ \ m = \frac{F}{a}\\\\m = \frac{1200 \ N}{3\frac{N}{kg}}\\\\m = 400 \ kg[/tex]
[tex]F = 1200 \ N\\a = 3\frac{m}{s^{2}} = 3\frac{N}{kg}\\m = ?\\\\Z \ II \ zasady \ dynamiki:\\\\a = \frac{F}{m} \ \ \rightarrow \ \ m = \frac{F}{a}\\\\m = \frac{1200 \ N}{3\frac{N}{kg}}\\\\m = 400 \ kg[/tex]