Odpowiedź:
1.
[tex]1\frac{1}{2}+3\frac{3}{4} = \frac{6}{4}+\frac{15}{4}=\frac{21}{4} = 5\frac{1}{4}[/tex]
2.
[tex](2\frac{1}{2}-5\frac{3}{5})^{2} -2 = (\frac{25}{10} -\frac{56}{10})^{2}-2 = (-\frac{31}{10} )^{2} -2 = \frac{961}{100}-2 = 9\frac{61}{100} -2 = 7\frac{61}{100}[/tex]
3.
[tex]P = \frac{1}{2}ah[/tex] [tex]= 2\frac{1}{3}*1\frac{1}{2}:2 = \frac{7}{3}*\frac{3}{2}:2 = \frac{7}{2}:2 = \frac{7}{4} = 1\frac{1}{4}[/tex]
Liczę na naj jeśli dobrze <3
