Odpowiedź:
W - [tex]O_{2}[/tex] Tlen
X - [tex]CH_{3}COOC_{4}H_{9}[/tex] Etanian butylu
Y - [tex]H_{2}O[/tex] Woda
Z - [tex]CH_{3}COOK[/tex] Etanian potasu
1. [tex]CH_{3}COOH + C_{4}H_{9}OH = CH_{3}COOC_{4}H_{9} + H_{2}O[/tex]
2. [tex]2K + 2CH_{3}COOH = 2CH_{3}COOK + H_{2}[/tex]
3. [tex]C_{4}H_{9}OH + 6O_{2} = 4CO_{2} + 5H_{2}O[/tex]
4. [tex]CH_{3}COOC_{4}H_{9} + 5O_{2} = 3CO_{2} + 6H_{2}O[/tex]
5. [tex]2H_{2}+O_{2} = 2H_{2}O[/tex]
