[tex]Zadanie\\\\\frac{2}{3}x-\frac{1}{6}=3\ \ \mid\cdot6\\\\4x-1=18\ \ \mid+1\\\\4x=19\ \ \mid:4\\\\x=\frac{19}{4}\\\\x=4\frac{3}{4}\\\\\\\frac{x}{2}+\frac{1}{3}=\frac{7}{6}\ \ \mid \cdot6\\\\3x+2=7\ \ \mid-2\\\\3x=5\ \ \mid:3\\\\x= \frac{5}{3}\\\\x=1\frac{2}{3}\\\\\\y +\frac{3}{2}-(1-y)=3,5\\\\y+1,5-1+y=3,5\\\\2y+0,5=3,5\ \ \mid-0,5\\\\2y=3\ \ \mid:2 \\\\y=1,5[/tex]
[tex]0,2x+0,3=1,3\ \ \mid\cdot10\\\\2x+3=13\ \ \mid-3\\\\2x=10\ \ \mid:2\\\\x=5\\\\\\0,4x +2,3=1,2x-2,5\ \ \mid\cdot10\\\\4x+23=12x-25\ \ \mid-23\\\\4x=12x-48\ \ \mid-12x \\\\-8x=-48\ \ \mid:(-8)\\\\x=6[/tex]
