Odpowiedź:
[tex]\sqrt{6}(3\sqrt{12}-\sqrt{3})=3\sqrt{6\cdot12}-\sqrt{18}=3\sqrt{72}-\sqrt{9\cdot2}=3\sqrt{36\cdot2}-3\sqrt{2}=\\\\=3\cdot6\sqrt{2}-3\sqrt{2}=18\sqrt{2}-3\sqrt{2}=15\sqrt{2}[/tex]
