[tex]a)\\\\prostokat:\\bok:\ a=5\sqrt{3}\\bok:\ b=2\sqrt{6}\\\\pole\ prostokata:\\\\P=a*b\\\\P=5\sqrt{3}*2\sqrt{6}=10\sqrt{3*6}=10\sqrt{18}=10\sqrt{9*2}=10*3\sqrt{2}=30\sqrt{2}\ \ \ [j^2][/tex]
[tex]b)\\\\trojkat:\\podstawa:\ a=2\sqrt{2}+\sqrt{2}=3\sqrt{2}\\wysokosc:\ h =\frac{2\sqrt{6}}{3}\\\\pole\ trojkata:\\\\P=\frac{1}{2}a*h\\\\P= \frac{1}{\not{2}^1}*\not{3}^1\sqrt{2}*\frac{\not{2}^1\sqrt{6}}{\not{3}^1}=\sqrt{2*6}=\sqrt{12}=\sqrt{4*3}=2\sqrt{3}\ \ \ [j^2][/tex]
[tex]c)\\\\trapez:\\podstawa\ dolna:\ a= \sqrt{5}+2\sqrt{5}=3\sqrt{5}\\podstawa\ gorna:\ b=2\sqrt{5}\\wysokosc:\ h = \sqrt{15}\\\\pole\ trapezua:\\\\P=\frac{a+b}{2} *h\\\\P= \frac{3\sqrt{5}+2\sqrt{5}}{2}*\sqrt{15}=\frac{5\sqrt{5}}{2}*\sqrt{15}=\frac{5\sqrt{75}}{2}=\frac{5\sqrt{25*3}}{2}=\frac{5*5\sqrt{ 3}}{2}=\\\\=\frac{25\sqrt{3}}{2}=12,5\sqrt{3}\ \ \ [j^2][/tex]
