Odpowiedź :
[tex]dane:\\F = 600 \ N\\m = 300 \ kg\\szukane:\\a = ?\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m}\\\\a = \frac{600 \ N}{300 \ kg} = 2\frac{N}{kg} = 2\frac{m}{s^{2}}[/tex]
[tex]dane:\\F = 600 \ N\\m = 300 \ kg\\szukane:\\a = ?\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m}\\\\a = \frac{600 \ N}{300 \ kg} = 2\frac{N}{kg} = 2\frac{m}{s^{2}}[/tex]