Odpowiedź :
[tex]\dfrac{2n+2n+2+2n+4+2n+6}{4}=\dfrac{2n+2+2n+4}{2}\\\\\dfrac{8n+12}{4}=\dfrac{4n+6}{2}\\\\2n+3=2n+3[/tex]
L=P a więc jest.
[tex]\dfrac{2n+2n+2+2n+4+2n+6}{4}=\dfrac{2n+2+2n+4}{2}\\\\\dfrac{8n+12}{4}=\dfrac{4n+6}{2}\\\\2n+3=2n+3[/tex]
L=P a więc jest.