Odpowiedź:
Zad.1
p = [tex]\frac{-3}{-4}[/tex] = [tex]\frac{3}{4}[/tex]
q = [tex]\frac{-1}{-8}[/tex] = [tex]\frac{1}{8\\}[/tex]
Δ
[tex]3^{2} - 4 * -2 * -1 = 9 - 8 = 1\\\sqrt{1} = 1[/tex]
Postać kanoniczna:
-2(x - [tex]\frac{3}{4}[/tex])² + [tex]\frac{1}{8}[/tex]
Zad.2
a = [tex]\frac{5}{6}[/tex]
b = -2ap = -2 * [tex]\frac{5}{6} * - 1 = \frac{10}{6} = 1\frac{2}{3}[/tex]
c = ap² + q = [tex]\frac{5}{6} * 1 + (-3) = -\frac{1}{6}[/tex]
f(x) = [tex]\frac{5}{6}x^{2} + 1\frac{2}{3}x - \frac{1}{6}[/tex]
