Odpowiedź :
5 + 3|x - 2| =< 11 i xeC
3|x - 2| =< 6
3(x-2) =< 6 v. 3(x-2)>= -6
3x -6 <= 6. v. 3x-6>= -6
3x =< 12. v. 3x >= 0
z=< 4 v x>= 0
xe <0,4>
x = { 0,1,2,3,4}
5 + 3|x - 2| =< 11 i xeC
3|x - 2| =< 6
3(x-2) =< 6 v. 3(x-2)>= -6
3x -6 <= 6. v. 3x-6>= -6
3x =< 12. v. 3x >= 0
z=< 4 v x>= 0
xe <0,4>
x = { 0,1,2,3,4}