Odpowiedź:
W zadaniu chodzi o to, żeby zastąpić x i y wartościami x= -2 oraz y = -3
a) 4 * -3 -([tex]-2^{2}[/tex]) = -12+ -4 = -12-4 = -16
b) [tex]-2^{2}[/tex] - 2 * -3 + 7 = 4 + 6 + 7 = 10+7 = 17
c) 2*-2*-3 - 3*-2 + 2*-3 = -4*-3 + 6 - 6 = 12
d) 4 - 3* -3 + 2*-2 = 4+9-4= 13-4= 9
e)[tex]-2^{3}[/tex] + [tex]-2^{2}[/tex] - 4*-3 = -8 + 4 + 12 = -4+12 = 8
f) 6 * -3-( [tex]-2^{3}[/tex]) + 3*-2 + 2 = -18 + 8 + -6 + 2 = -10 -4 = -14
g) 3*-2 - 5*-3 + 2 = -6+15 + 2 = 9 + 2 = 11
h)[tex]-3^{2}[/tex] - 5 * [tex]-2^{2}[/tex] - 7 = 9 -5*4-7 = 9 - 20 - 7 = -11 - 7 = -18
i) 2*-2*-3 - 3*-3 - 7 * -2 = -4*-3 +9 +14 = 12 + 23 = 35
j) 5*-2 -3*-3 + 4 = -10 +9 +4 = -1+4 = 3
k)[tex]-2^{2}[/tex] - [tex]-2^{3}[/tex] + 5*-3 = 4 + 8 - 15 = 12-15 = -3
