Odpowiedź :
[tex]dane:\\m = 300 \ dag = 3 \ kg\\h = 200 \ cm = 2 \ m\\g = 10\frac{m}{s^{2}}\\szukane:\\E_{p} = ?\\\\E_{p} = mgh\\\\E_{p} = 3 \ kg\cdot10\frac{m}{s^{2}}\cdot2 \ m\\\\E_{p} = 60 \ J\\\\Odp. \ a)[/tex]
[tex]dane:\\m = 300 \ dag = 3 \ kg\\h = 200 \ cm = 2 \ m\\g = 10\frac{m}{s^{2}}\\szukane:\\E_{p} = ?\\\\E_{p} = mgh\\\\E_{p} = 3 \ kg\cdot10\frac{m}{s^{2}}\cdot2 \ m\\\\E_{p} = 60 \ J\\\\Odp. \ a)[/tex]