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współrzedne wierzcholka w paraboli: f(x) = 2x2 + 4x -6

Odpowiedź :

f(x) = 2x² + 4x - 6

W = (p, q)

p = -b/2a

q = -∆/4a

a = 2, b = 4, c = -6

∆ = b² - 4ac

∆ = 4² - 4 * 2 * (-6) = 16 + 48 = 64

p = -4/4 = -1

q = -64/8 = -8

W = (-1, -8)