Odpowiedź:
[tex](x+3)^2=-4x^2+x+109\\x^2+6x+9 =-4x^2+x+109 /+4x^2-x-109\\5x^2+5x-100=0/:5\\x^2+x-20=0\\\Delta = 1 -4\cdot1\cdot(-20)=1+80=81\\\sqrt{\Delta}=9\\x_1 = \frac{-b-\sqrt{\Delta}}{2a}=\frac{-1-9}{2}=\frac{-10}{2}=-5\\x_1 = \frac{-b+\sqrt{\Delta}}{2a}=\frac{-1+9}{2}=\frac{8}{2}=4[/tex]
