Odpowiedź :
1.
[tex]dane:\\m = 6 \ kg\\F_{w} = 30 \ N\\szukane:\\a = ?\\\\a = \frac{F_{w}}{m}\\\\a = \frac{30 \ N}{6 \ kg} = 5\frac{N}{kg} = 5\frac{m}{s^{2}}[/tex]
2.
[tex]dane:\\m = 4 \ kg\\a = 5\frac{N}{kg}\\szukane:\\F = ?\\\\F = m\cdot a\\\\F = 4 \ kg\cdot5\frac{N}{kg}\\\\F = 20 \ N[/tex]
3.
[tex]dane:\\F = 8 \ N\\a = 0,2\frac{N}{kg}\\szukane:\\m = ?\\\\m = \frac{F}{a}\\\\m = \frac{8 \ N}{0,2\frac{N}{kg}}\\\\m = 40 \ kg[/tex]