Plz na teraz zadanie w załączniku

[tex]zad.a\\3x+7=-12x-18\\3x+12x=-18-7\\\\15x=-25~~~\arrowvert \div15\\\\x = - \frac{25}{15} \\\\x = - \frac{5}{3} \\\\x = - 1\frac{2}{3}[/tex]
[tex]zad.b\\2(10-5x) = 3(2-x) -4(x-1)\\\\20-10x =6-3x-4x+4\\\\20-10x= 10-7x\\\\-10x+7x=10-20\\\\-3x=-10~~\arrowvert \div (-3)\\\\x=\frac{10}{3}\\\\x= 3\frac{1}{3}[/tex]
[tex]zad.c\\2,6x+1\frac{2}{5}=\frac{4}{5}(4,5x- 15)+7\\\\2,6x+1,4=0,8(4,5x- 15)+7\\\\2,6x+1,4=3,6x-12+7\\\\2,6x -3,6x = -12+7-1,4\\\\-x = - 6,4~~\arrowvert \div(-1)\\\\x=6,4[/tex]
[tex]zad.d\\x+\frac{6-3x}{2} = -\frac{1}{6} +\frac{-3-x}{3} ~~~\arrowvert \cdot 6\\\\6x+3(6-3x) = -1+2(-3-x)\\\\6x + 18 -9x = -1 -6-2x\\\\6x-9x+2x = -1-6-18\\\\-x = - 25~~\arrowvert \div (-1)\\\\x = 25[/tex]
[tex]zad.e\\\frac{5}{4}x-3(\frac{4}{3} -2x) =\frac{2-3x}{4} - \frac{x+2}{5} ~~~\arrowvert \cdot 20\\\\25x-60(\frac{4}{3} -2x) =5(2-3x)-4(x+2)\\\\25x -80 + 120x = 10 -15x-4x-8\\\\145x-80 = 2-19x\\\\145x+19x = -8+80\\\\164x = 72~~\arrowvert \div164\\\\x = \frac{72}{164} \\\\x=\frac{18}{41}[/tex]