Odpowiedź:
[tex]2\frac{1}{4}+3\frac{3}{4}=5\frac{4}{4}=6\\\\6:7=\frac{6}{7}\\\\\frac{6}{7}+2\frac{5}{7}=2\frac{11}{7}=3\frac{4}{7}\\\\3\frac{4}{7}-3=\frac{4}{7}\\\\\frac{4}{\not7}\cdot\not7=4\\\\4-\frac{1}{3}=3\frac{3}{3}-\frac{1}{3}=3\frac{2}{3}\\\\3\frac{2}{3}+1\frac{2}{3}=4\frac{4}{3}=5\frac{1}{3}\\\\5\frac{1}{3}-\frac{1}{3}=5\\\\5-2\frac{3}{4}=4\frac{4}{4}-2\frac{3}{4}=2\frac{1}{4}[/tex]
