Odpowiedź i szczegółowe wyjaśnienie:
[tex]\left \{ {{3x+y=3} \atop {2x-3y=2}} \right. \\\\\left \{ {{y=3-3x} \atop {2x-3(3-3x)=2}} \right. \\\\\left \{ {{y=3-3x} \atop {2x-9+9x=2}} \right.\\\\\left \{ {{y=3-3x} \atop {11x=2+9}} \right.\\\\\left \{ {{y=3-3x} \atop {11x=11\ /:11}} \right.\\\\\left \{ {{y=3-3x} \atop {x=1}} \right.\\\\\left \{ {{y=3-3\cdot 1} \atop {x=1}} \right.\\\\\left \{ {{y=0} \atop {x=1}} \right.[/tex]
