[tex]dane:\\d = 1200\frac{kg}{m^{3}}\\V = 1 \ cm \times 5 \ cm\times 10 \ cm = 50 \ cm^{3} = 0,00005 \ m^{3}\\g = 10\frac{N}{kg}\\szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\F_{w} = d\cdot g\cdot V\\\\F_{w} = 1200\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot 0,00005 \ m^{3}\\\\F_{w} = 0,6 \ N[/tex]
