Odpowiedź :
2 Fe2O3 + 3 C - > 4 Fe + 3 CO2
M Fe = 56g/mol
M O = 16g/mol
M Fe2O3 = 2 * 56g/mol + 3 * 16g/mol = 160g/mol
2 * 160g Fe2O3 --- 4 * 56g Fe
x -------------- 500g Fe
x = 320 * 500 / 224 = 714, 28g Fe2O3
2 Fe2O3 + 3 C - > 4 Fe + 3 CO2
M Fe = 56g/mol
M O = 16g/mol
M Fe2O3 = 2 * 56g/mol + 3 * 16g/mol = 160g/mol
2 * 160g Fe2O3 --- 4 * 56g Fe
x -------------- 500g Fe
x = 320 * 500 / 224 = 714, 28g Fe2O3