Odpowiedź :
[tex]log_{6}4 + log_{6}27 - log_{6}3 = log_{6}(4\cdot27)-log_{6}3 = log_{6}\frac{4\cdot27}{3} = log_{6}36} = log_{6}6^{2} = 2[/tex]
[tex]log_{6}4 + log_{6}27 - log_{6}3 = log_{6}(4\cdot27)-log_{6}3 = log_{6}\frac{4\cdot27}{3} = log_{6}36} = log_{6}6^{2} = 2[/tex]