[tex]a)\\\\\frac{ x-3}{2} =\frac{ 4+0,5x }{3}\ \ |*6\\\\3(x-3)=2(4+0,5x)\\\\3x-9=8+x\\\\3x-x=8+9\\\\2x=17 \ \ |:2\\\\x=\frac{17}{2}[/tex]
[tex]spr.\\\\\frac{ \frac{17}{2}-3}{2} =\frac{ 4+0,5 *\frac{17}{2} }{3}\\\\\frac{ \frac{17}{2}- \frac{6}{2}}{2} =\frac{ 4+ \frac{1}{2} *\frac{17}{2} }{3}\\\\\frac{ \frac{11}{2} }{2} =\frac{ \frac{16}{4}+ \frac{17}{4} }{3} \\\\\frac{11}{4}=\frac{\frac{33}{4}}{3}\\\\\frac{11}{4}= \frac{33}{12} \\\\\frac{11}{4}= \frac{11}{4}\\\\L=P[/tex]
[tex]4(2c-7)=42c\\\\8c-28=42c\\\\8c-42c=28\\\\-34c=28\ \ :(-34)\\\\c=-\frac{28}{34}=-\frac{14}{17}[/tex]
[tex]spr.\\\\ 4(2 *(-\frac{14}{17})-7)=42 *(-\frac{14}{17})\\\\ 4( - \frac{147}{17} )= -\frac{588}{17}\\\\ -\frac{588}{17}=-\frac{588}{17}\\\\L=P[/tex]
