Odpowiedź:
[tex]a)\ \ (2\sqrt{7})^2=2^2*(\sqrt{7})^2=4*7=28\\\\b)\ \ (\frac{3\sqrt{3}}{2})^2=\frac{(3\sqrt{3})^2}{2^2}=\frac{3^2*(\sqrt{3})^2}{4}=\frac{9*3}{4}=\frac{27}{4}=6\frac{3}{4}\\\\c)\ \ 4\sqrt{5^2}=4*5=20\\\\d)\ \ \frac{1}{3}\sqrt{6}*3\sqrt{6}=\frac{1}{3}*3*6=1*6=6\\\\e)\ \ 7\sqrt[3]{5^2}=7\sqrt[3]{25}\\\\f)\ \ (2\sqrt[3]{3})^3=2^3*(\sqrt[3]{3})^3=8*3=24[/tex]
