Odpowiedź :
[tex]\left \{ {{3x + y = -2} \atop {6x - 5y = 3}} \right. \\\left \{ {{y=-2 - 3x} \atop {6x - 5(-2-3x) = 3}} \right. \\\left \{ {{y=-2-3x} \atop {6x + 10 + 15x = 3/-10}} \right. \\\left \{ {{y= -2 - 3x} \atop {21x = -7 /:21}} \right.[/tex]
[tex]\left \{ {{y= -2 - 3x} \atop {x=-\frac{1}{3} }} \right.[/tex]
[tex]\left \{ {{y= -2 - 3*(-\frac{1}{3}) } \atop {x=-\frac{1}{3} }} \right. \\\left \{ {{y= -2 + 1 } \atop {x=-\frac{1}{3} }} \right. \\\left \{ {{y=-1} \atop {x=-\frac{1}{3} }} \right.[/tex]